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Consider the following y=(t/x⁴)+(x/t)
a) Find dy/dx
b) Find dy/dt

User AlphaRL
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1 Answer

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Final answer:

To find dy/dx, differentiate the given equation with respect to x. To find dy/dt, differentiate the equation with respect to t.

Step-by-step explanation:

To find dy/dx, we need to differentiate the given equation y=(t/x⁴)+(x/t) with respect to x. Using the power rule of differentiation, we get:

dy/dx = d/dx [(t/x⁴) + (x/t)]

= ((d/dx)(t/x⁴)) + ((d/dx)(x/t))

= (1/x⁴)(d/dx)(t) + (1/t)(d/dx)(x)

= -4t/x⁵ + 1/t

Therefore, dy/dx = -4t/x⁵ + 1/t.

To find dy/dt, we differentiate the equation with respect to t:

dy/dt = d/dt [(t/x⁴) + (x/t)]

= ((d/dt)(t/x⁴)) + ((d/dt)(x/t))

= (1/x⁴)(d/dt)(t) + (1/t)(d/dt)(x)

= 1/x⁴ - x/t²

Therefore, dy/dt = 1/x⁴ - x/t².

User Renato Heeb
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