Question

An electron starting from rest acquires 5.4 kev of ke in moving from point A to point B . How much KE would a proton acquire, starting from rest at B and moving to point A. Determine the ratio of their speeds at the end oftheir respective trajectories.

Answer 1

To find the ratio of speeds between a proton and an electron, we need to calculate the kinetic energy acquired by the proton when moving from point B to point A. The velocity of the proton will be approximately the square root of 1836 times larger than the velocity of the electron.

Step-by-step explanation:

To calculate the ratio of velocities, we need to find the kinetic energy (KE) acquired by a proton when accelerated from rest from point B to point A. The electron acquires 5.4 keV of KE when moving from A to B. Since KE = 1/2mv^2, we can calculate the velocity of the proton when it reaches point A using the same formula. The mass of a proton is about 1836 times that of an electron, so the velocity of the proton will be about √1836 times larger than the velocity of the electron. Therefore, the ratio of their speeds will be approximately √1836.