Final answer:
The final molarity of a solution made by diluting 100 ml of a 2.5 M solution to 200 ml is 1.25 M, calculated using the dilution equation M1V1 = M2V2.
Step-by-step explanation:
To determine the molarity of a solution after dilution, we can use the formula M1V1 = M2V2, where M1 is the initial molarity, V1 is the initial volume, M2 is the final molarity, and V2 is the final volume. In the case of diluting 100 ml of a 2.5 M solution to 200 ml, we apply this formula:
(2.5 M)(100 ml) = M2(200 ml)
To solve for M2, we divide both sides by 200 ml:
M2 = (2.5 M)(100 ml) / (200 ml)
M2 = (250 mol/ml) / (200 ml)
M2 = 1.25 M
The final molarity of the solution after dilution is 1.25 M.
To calculate the molarity of the solution after dilution, we can use the dilution equation: M1V1 = M2V2. M1 is the initial molarity, V1 is the initial volume, M2 is the final molarity, and V2 is the final volume. In this case, the initial molarity (M1) is 2.5 M, the initial volume (V1) is 100 mL, and the final volume (V2) is 200 mL. Plugging these values into the equation:
(2.5 M)(100 mL) = M2(200 mL)
Solving for M2, the final molarity:
M2 = 1.25 M
Therefore, the molarity of the solution after diluting 100 mL of a 2.5 M solution to 200 mL is 1.25 M.