Question

if 50,000 j of heat are added to 0.6 kg of water, which has a specific heat of 4,184 j/(kgoc) and is at an initial temperature of 25oc, what is the final temperature of the water (in oc)?

Answer 1

To find the final temperature, we can use the equation Q = mcΔT. Plugging in the given values, we can calculate the change in temperature and add it to the initial temperature.

Step-by-step explanation:

To find the final temperature of the water, we can use the equation:

Q = mcΔT

Where:

Q is the heat energy transferred to the water

m is the mass of the water

c is the specific heat capacity of water

ΔT is the change in temperature

Plugging in the given values:

Q = 50,000 J

m = 0.6 kg

c = 4,184 J/(kg·°C)

ΔT = ? (final temperature - initial temperature)

Rearranging the equation to solve for ΔT:

ΔT = Q / (mc)

Substituting the values:

ΔT = 50,000 J / (0.6 kg × 4,184 J/(kg·°C))

Calculating the ΔT:

ΔT ≈ 3.56°C

To find the final temperature, we add the change in temperature to the initial temperature:

Final Temperature = 25°C + ΔT

Final Temperature ≈ 28.56°C