Final answer:
No, because w does not contain the zero vector.
Step-by-step explanation:
For w to be a subspace of v, it must fulfill three conditions:
- It must be a subset of v.
- It must be closed under vector addition.
- It must be closed under scalar multiplication.
In this case, option 4 states that w does not contain the zero vector. Since the zero vector is a necessary element for a subspace, we can conclude that w is not a subspace of v.