Final answer:
The balanced chemical equation for the reaction of B2H6(g) with Cl2(g) to form BCl3(g) and HCl(g) is B2H6(g) + 6 Cl2(g) → 2 BCl3(g) + 6 HCl(g). It shows a molar ratio of 1:6:2:6 for B2H6, Cl2, BCl3, and HCl respectively.
Step-by-step explanation:
The balanced chemical equation for the reaction between B2H6 gas and Cl2 gas to produce BCl3 gas and HCl gas is:
B2H6(g) + 6 Cl2(g) → 2 BCl3(g) + 6 HCl(g)
To balance this equation, you start with the reactants and their products and compare the number of atoms of each element on both sides of the equation. Here, you have 2 boron (B) atoms on both sides, 6 hydrogen (H) atoms on both sides, and 12 chlorine (Cl) atoms on both sides. The coefficients indicate the molar ratio of the reactants and products. Therefore, for every 1 mole of B2H6 reacted, 6 moles of Cl2 are required, yielding 2 moles of BCl3 and 6 moles of HCl.
The balanced chemical equation for the reaction b2h6(g) + 6 cl2(g) → 2 bcl3(g) + 6 hcl(g) is:
B2H6(g) + 6 Cl2(g) → 2 BCl3(g) + 6 HCl(g)
In this equation, b2h6 reacts with 6 cl2 to produce 2 bcl3 and 6 hcl. The coefficients in the equation ensure that there are an equal number of each type of atom on both sides of the equation, making it balanced.