Answer:
x−2y+5=0
Explanation:
x2+y2−2x+4y=15
differentiating both sides with respect to x
2x+2yy′−2+4y′=0
2x−2+(2y+4)y′=0
y′=2−2x2y+4
y′(−1,2)=2+24+4=12
slope of tangent at (- 1, 2)=12
Equation of the tangent is
y−2=12(x+1)
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