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Find, correct to four decimal places, the length of the curve of intersection of the cylinder 16x² y² = 16 and the plane x y z = 14?

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Final answer:

To find the length of the curve of intersection between the cylinder and the plane, you need to parameterize the curve using a parameter t and then use numerical methods to approximate the result.

Step-by-step explanation:

To find the length of the curve of intersection between the cylinder and the plane, we need to parameterize the curve using a parameter t. Let's express x and y in terms of t first. From the equation of the cylinder, we have 16x^2y^2 = 16. Dividing both sides by 16, we obtain x^2y^2 = 1. Taking the square root of both sides, we get xy = ±1.

Now, substituting x = t and y = 1/t into the equation of the plane, we have t(1/t)z = 14, which simplifies to z = 14. Therefore, the parameterization of the curve is x = t, y = 1/t, and z = 14.

The length of the curve can be found using the arc length formula: ∫ sqrt((dx/dt)^2 + (dy/dt)^2 + (dz/dt)^2) dt. Substituting the parameterization, we have ∫ sqrt(1 + (-1/t^2)^2 + 0) dt. Simplifying, we get ∫ sqrt(1 + 1/t^4) dt.

Since this integral does not have an elementary antiderivative, we need to use numerical methods to approximate the result. Using a numerical integration method, such as the trapezoidal rule or Simpson's rule, we can compute an approximate value of the integral to find the length of the curve of intersection.

User Nilesh Gule
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