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Find d2y/dx2 in terms of x and y for the equation x²y² - 16x = 3?

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Final answer:

To find d2y/dx2 in terms of x and y for the equation x²y² - 16x = 3, differentiate the equation twice with respect to x. Simplify the resulting expression to find the second derivative.

Step-by-step explanation:

To find d2y/dx2 in terms of x and y for the equation x²y² - 16x = 3, we need to differentiate the equation twice with respect to x. Let's start by differentiating both sides of the equation:

d/dx(x²y² - 16x) = d/dx(3)

Using the power rule and the chain rule, we get:

2x(y²) + x²(2y)(dy/dx) - 16 = 0

Simplifying this expression gives:

2xy² + 2x²y(dy/dx) - 16 = 0

Now, differentiating again with respect to x:

d/dx(2xy² + 2x²y(dy/dx) - 16) = d/dx(0)

Using the power rule, the product rule, and the chain rule, we get:

2y² + 4xy(dy/dx) + 2x²(dy/dx)² + 2x²(d²y/dx²) - 0 = 0

Simplifying this expression gives the second derivative:

2y² + 4xy(dy/dx) + 2x²(dy/dx)² + 2x²(d²y/dx²) = 0

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