Final answer:
The maximum mass of H₂O that can be produced by combining 66.8 g of each reactant is 37.62 g of H₂O.
Step-by-step explanation:
To find the maximum mass of H₂O that can be produced by combining 66.8 g of each reactant, we need to determine the limiting reactant. Let's compare the moles of hydrogen and oxygen:
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- 66.8 g of H₂O / 18.02 g/mol = 3.71 mol
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- 66.8 g of O₂ / 32.0 g/mol = 2.09 mol
Since the mole ratio of H₂O to O₂ is 2:1, the limiting reactant is O₂ because it is available in lower quantity. To find the maximum mass of H₂O produced, we multiply the moles of O₂ by the molar mass of H₂O:
2.09 mol O₂ x 18.02 g/mol H₂O = 37.62 g of H₂O