Final answer:
The de Broglie wavelength of a hydrogen atom traveling at 475 m/s is approximately 3.52 x 10^-10 meters.
Step-by-step explanation:
To calculate the de Broglie wavelength of a hydrogen atom traveling at 475 m/s, we can use the de Broglie equation:
λ = h / (m * v)
where λ is the de Broglie wavelength, h is Planck's constant (6.626 x 10^-34 kg m²/s), m is the mass of the hydrogen atom (1.67 x 10^-27 kg), and v is the velocity of the hydrogen atom.
Substituting the given values into the equation, we have:
λ = (6.626 x 10^-34 kg m²/s) / (1.67 x 10^-27 kg * 475 m/s)
Calculating this expression, we find that the de Broglie wavelength of the hydrogen atom is approximately 3.52 x 10^-10 meters.