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Evaluate the integral below using integration by parts given that u=ln(2x⁵) and dv=5x²dx. ∫5ln(2x⁵)x²dx?

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Final answer:

To evaluate the given integral using integration by parts, assign the values u = ln(2x^5) and dv = 5x^2 dx. Apply the integration by parts formula to find the result and simplify the expression.

Step-by-step explanation:

To evaluate the integral, we can use the integration by parts method. Let's start by assigning the values of u and dv. In this case, u = ln(2x^5) and dv = 5x^2 dx.

According to the integration by parts formula, we have:

∫ u dv = uv - ∫ v du,

Let's find du by differentiating u:

du = d(ln(2x^5)) = (1/(2x^5))(10x^4) = 5/x dx,

Now, we can substitute these values into the formula:

∫ 5ln(2x^5) x^2 dx = uv - ∫ v du = ln(2x^5) * x^2 - ∫ 5/x * x^2 dx.

Simplifying further, we have:

∫ 5ln(2x^5) x^2 dx = x^2 ln(2x^5) - 5 ∫ x dx = x^2 ln(2x^5) - (5/2)x^2 + C,

where C is the constant of integration.

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