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Obtener la ecuación de la recta que pasa por el punto (6-8) y tiene como pendiente m=-2

User Ziu
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1 Answer

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The equation of the line is y = -2x+ 4.

To obtain the equation of a line in English that passes through the point (6, -8) and has a slope of m = -2, you can use the point-slope form of the equation of a line:


\[ y - y_1 = m(x - x_1) \]

where:

-
\( (x_1, y_1) \) is the given point (6, -8),

- m is the slope (-2).

Substitute the values into the formula:


\[ y - (-8) = -2(x - 6) \]

Simplify the equation:


\[ y + 8 = -2x + 12 \]

Now, isolate y on one side of the equation:


\[ y = -2x + 12 - 8 \]

Combine constants:


\[ y = -2x + 4 \]

So, the equation of the line is
\( y = -2x + 4 \).

User Rizwan Ahmed
by
8.3k points
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