Final answer:
To find the pH of a mixture of 0.300 M HF and 0.100 M HClO, calculate the concentration of H^+ ions from the dissociation of HF and the concentration of ClO^- ions from the dissociation of HClO. Then, use the equation pH = -log[H^+] to calculate the pH of the mixture.
Step-by-step explanation:
To find the pH of a mixture that is 0.300 M in HF and 0.100 M in HClO, we need to consider the dissociation of both acids. HF will partially dissociate, producing H^+ ions, while HClO will fully dissociate, producing ClO^- ions.
First, let's calculate the concentration of H^+ ions from the dissociation of HF using the given concentration:
[H^+] = 0.300 M * alpha
Next, let's calculate the concentration of ClO^- ions from the dissociation of HClO:
[ClO^-] = 0.100 M
The pH of the mixture can be calculated using the equation: pH = -log[H^+]. Substitute the values of [H^+] obtained from the dissociation of HF and [ClO^-], and calculate the pH.
pH = -log([H^+]) = -log([H^+]_HF + [H^+]_HClO)