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HELP ME PLSS 100 points!!!

Task 2
Part 1. Create two radical equations: one that has an extraneous solution, and one that does not have an extraneous solution. Use the equation below as a model:

a√x+b+c=d

Use a constant in place of each variable a, b, c, and d. You can use positive and negative constants in your equation.

Part 2. Show your work in solving the equation. Include the work to check your solution and show that your solution is extraneous.

Part 3. Explain why the first equation has an extraneous solution and the second does not.

User Wole
by
2.8k points

1 Answer

19 votes
19 votes

Answer:5+10-15=30

5=35

=7

х=49

5√49+10-15=30

30=30

+1+7=4

=-4

Explanation:

User Ilan Frumer
by
2.5k points