Question

David is driving a steady 27.0 m/s when he passes Tina, who is sitting in her car at rest. Tina begins to accelerate at a steady 2.30 m/s² at the instant when David passes. What is Tina's velocity after 5 seconds?

Answer 1

By applying the basic kinematic equation, we find that Tina's velocity after 5 seconds of acceleration at a rate of 2.30 m/s² is 11.5 m/s.

Step-by-step explanation:

Tina's velocity after 5 seconds can be calculated using the basic physics equation for acceleration. The equation needed is:

v = u + at

Where:

• v is the final velocity,
• u is the initial velocity (which is 0 m/s since Tina is at rest),
• a is the acceleration,
• t is the time.

Plugging in Tina's acceleration (2.30 m/s2) and the time interval (5 seconds), we get:

v = 0 m/s + (2.30 m/s2)(5 s) = 11.5 m/s.

Therefore, Tina's velocity after 5 seconds is 11.5 m/s.