Final answer:
The expression x'y is already a minterm, representing the case where x is false (x') and y is true in Boolean algebra. Thus, x'y in sum-of-minterms form is simply x'y itself, corresponding to the minterm m2.
Step-by-step explanation:
The question asks to expand the expression x'y into a sum-of-minterms form. A minterm is a specific type of term in Boolean algebra that represents a unique combination of variables in a truth table. In Boolean algebra, expansion of an expression into sum-of-minterms involves expressing the function as a sum (OR) of minterms, where each minterm is a product (AND) of all the variables in their true or complemented form. For a two-variable expression such as x'y, which implies NOT x AND y, there are four possible minterms for two variables x and y: m0 = xy, m1 = xy', m2 = x'y, and m3 = x'y'.
To express x'y in sum-of-minterms form, one must consider the truth table for x and y. In this truth table, the expression x'y is true only for the combination where x is 0 and y is 1, which corresponds to the minterm m2. Therefore, the sum-of-minterms form of x'y is simply m2, or in full form, x'y since it's the only minterm where the expression is true.