Final answer:
To evaluate the definite integral ∫(3t²j) dt from 0 to ?, find the antiderivative of 3t²j, substitute ? for t and evaluate it at the upper limit minus the lower limit.
Step-by-step explanation:
To evaluate the definite integral ∫(3t²j) dt from 0 to ?, we need to find the antiderivative of 3t²j with respect to t and evaluate it at the upper limit of integration minus the lower limit of integration.
The antiderivative of 3t²j is (t³/3)j, so the definite integral becomes [((t³/3)j)] evaluated from 0 to ?.
To evaluate the integral at the upper limit of integration ? and the lower limit of integration 0, we substitute ? for t in the antiderivative expression and then subtract the result of substituting 0 for t.