Final answer:
a. The average acceleration of the golf ball is 200,000 m/s². b. The distance that the golf ball travels during this time is 0.032 m. c. The ball squashes during the contact between the club head and the ball, which supports the answer to part b.
Step-by-step explanation:
a. To determine the average acceleration of the golf ball, we can use the equation for average acceleration: average acceleration = change in velocity / time. In this case, the change in velocity is from rest (0 m/s) to 80 m/s, and the time is 0.4 ms.
Plugging these values into the equation, we get:
average acceleration = (80 m/s - 0 m/s) / (0.4 ms / 1000)
= 200,000 m/s²
b. To determine the distance that the golf ball travels during this time, we can use the equation for distance: distance = initial velocity * time + 0.5 * acceleration * time^2. In this case, the initial velocity is 0 m/s, the acceleration is 200,000 m/s², and the time is 0.4 ms.
Plugging these values into the equation, we get:
distance = 0 * (0.4 ms / 1000) + 0.5 * 200,000 * (0.4 ms / 1000)^2
= 0.032 m
c. The observation that the ball squashes during the contact between the club head and the ball supports our answer to part b because when the ball squashes, it means that it is deforming. This deformation allows the ball to compress and expand, which results in a change in shape and a greater distance traveled due to the conversion of kinetic energy to potential energy and vice versa.