Final answer:
The energy of a photon emitted when an electron in a hydrogen atom undergoes a transition from n = 6 to n = 1 can be calculated using the formula: E = Rh(1/n²₁ - 1/n²₂). Substituting the values for n₁ and n₂, we can find the energy of the emitted photon.
Step-by-step explanation:
The energy of a photon emitted when an electron in a hydrogen atom undergoes a transition from n = 6 to n = 1 can be calculated using the formula:
E = Rh(1/n²1 - 1/n²2)
Where E is the energy of the photon, Rh is the Rydberg constant, and n₁ and n₂ are the initial and final energy levels of the electron respectively.
Using this formula, we can find the energy of the emitted photon by substituting n₁ = 6 and n₂ = 1:
E = Rh(1/1² - 1/6²) = Rh(1 - 1/36) = Rh(35/36).