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Find the point at which the line x=3+5t, y=-4, z=2t intersects the plane 2x+3y-2z=6.

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Final answer:

The point of intersection between the given line and plane is (9/4, -4, 3/2).

Step-by-step explanation:

The line is defined by the equations:

x = 3 + 5t

y = -4

z = 2t

The equation of the plane is 2x + 3y - 2z = 6.

To find the point of intersection, we can substitute the values of x, y, and z from the line equations into the plane equation:

2(3 + 5t) + 3(-4) - 2(2t) = 6

Simplifying this equation gives:

6 + 10t - 12 + 6t = 6

16t = 12

t = 12/16

t = 3/4

Substituting t back into the line equations gives:

x = 3 + 5(3/4)

y = -4

z = 2(3/4)

Simplifying these equations gives:

x = 9/4

y = -4

z = 3/2

Therefore, the point of intersection is (9/4, -4, 3/2).

User Mitun
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