Final answer:
The value of register t2 after executing the operations sll and OR on t0 and t1 is 0xbaaaaff8.
Step-by-step explanation:
This question relates to assembly language instructions on MIPS processors. The question involves two operations: a shift left logical (sll) and a bitwise OR (or). Initially, t0 is set to 0xaaaaaaaa and t1 is set to 0x12345678. The instruction sll t2, t0, 4 shifts the contents of register t0 to the left by 4 bits.
The value of t0 after the shift is 0xaaaaaaa0. The succeeding instruction or t2, t2, t1 performs a bitwise OR between the shifted value in t2 and t1, resulting in the final value of t2 as 0xbaaaaff8.