Final answer:
The integrated rate law for the given reaction is [A]t = 1.0 x 10⁻³ + Ct/5.0 x 10⁻².
Step-by-step explanation:
The integrated rate law for a zero-order reaction is given by [A]t = [A]o - kt, where [A]t is the concentration of reactant A at time t, [A]o is the initial concentration of A, k is the rate constant, and t is the time.
In this case, the reaction A ---- B+C is known to be zero order in A with a rate constant of -C/5.0 x 10⁻² mol/L s at 25°C. Given Ao = 1.0 x 10⁻³ M, we can substitute the values into the integrated rate law to get [A]t = 1.0 x 10⁻³ - (-C/5.0 x 10⁻²)t.
Therefore, the integrated rate law for this reaction is [A]t = 1.0 x 10⁻³ + Ct/5.0 x 10⁻².