Question

The air exhaled from the lungs of a smoker has a concentration of 200 ppm CO. Express the concentration as a percent.

Answer 1

The concentration of carbon monoxide (CO) in the exhaled air of a smoker is 200 ppm. To express this concentration as a percent, divide it by 10,000 and multiply by 100. The concentration is 2%.

Step-by-step explanation:

The concentration of carbon monoxide (CO) in the exhaled air of a smoker is given as 200 ppm (parts per million). To express this concentration as a percent, we need to convert it to a decimal by dividing it by 10,000.

200 ppm / 10,000 = 0.02

So, the concentration as a percent is 0.02 x 100 = 2%.