Final answer:
The task is to assign the first element of the array rowEx to xVal. This is achieved by using the index of the first element, which is 1 in MATLAB syntax. The correct code would be xVal = rowEx(1);.
Step-by-step explanation:
The given question pertains to working with arrays in a programming context, likely within MATLAB or a similar array-oriented programming language. The notation rowEx = [3:1:10] suggests the creation of a row vector that starts at 3 and increments by 1 up to 10. The task is to write a statement to set xVal to the first element of rowEx.
To accomplish this, you would typically use indexing to access the first element of the array rowEx. In MATLAB or similar languages, indexing starts at 1. Therefore, the code to set xVal to the first element of rowEx would be xVal = rowEx(1);.
To set xVal to the first element of rowEx, you can use the following statement:
xVal = rowex(1);
This statement assigns the first element of the array rowex to the variable xVal. In this case, the first element of rowex is 3, so xVal will be set to 3.