Final answer:
The parametric equations of the line are x = 0 + 9t, y = 1 + 0t, and z = 2 - 6t.
Step-by-step explanation:
To find the parametric equations for the line passing through the points (0, 1, 2) and (9, 1, -4), we can use the vector equation of a line. First, we find the direction vector by subtracting the coordinates of the two points: (Δx, Δy, Δz) = (9-0, 1-1, -4-2) = (9, 0, -6). We can then set up the parametric equations as follows:
x = 0 + 9t
y = 1 + 0t
z = 2 - 6t
where t is the parameter.