Final answer:
The evaluation of f(x) = ln(6) at x = 0 is simply the constant value ln(6) because it does not depend on x.
Step-by-step explanation:
The function f(x) = ln(6) is being evaluated at x = 0. However, since the natural logarithm of 6 is a constant, it does not depend on the variable x. Therefore, evaluating f(x) = ln(6) at any value of x, including x = 0, will simply yield the constant value ln(6).
Moreover, because the natural logarithm function and the exponential function are inverse functions of each other, they cancel each other out when applied sequentially. This means that In (ex) = x and elnx = x. This relationship does not apply directly to f(x) since it does not involve the variable x within its logarithmic function.