Final answer:
The maximum height reached by the shot is 2.30 m.
Step-by-step explanation:
To find the maximum height reached by the shot, we first need to find the time it takes for the shot to reach its maximum height. We can use the equation:
vf = vi + at
where vf is the final velocity, vi is the initial velocity, a is the acceleration, and t is the time. In this case, the initial velocity is 0 m/s, the acceleration is -30.0 m/s² (negative because it is directed opposite to the motion), and the final velocity at the maximum height is also 0 m/s. Solving for t, we get:
t = -vi / a
t = 0 / (-30.0)
t = 0 s
Since the time it takes for the shot to reach its maximum height is 0 seconds, this means that the maximum height is reached as soon as the shot is released. So, the maximum height is equal to the initial height, which is 2.30 m above the ground. Therefore, the correct answer is 2.30 m.