Question

Two large conducting parallel plates A and B are separated by 2.4 m. A uniform field of 1500 V/m, in the positive x-direction, is produced by charges on the plates. The center plane at x = 0.00 m is?

Answer 1

The potential difference between the two parallel conducting plates is 3600 V.

Step-by-step explanation:

The electric field strength between two parallel conducting plates can be determined using the formula:

E = V/d

Where E is the electric field strength, V is the potential difference between the plates, and d is the separation between the plates.

In this case, the electric field strength is 1500 V/m and the separation between the plates is 2.4 m. Therefore, the potential difference between the plates can be calculated as:

V = E * d

V = 1500 V/m * 2.4 m

V = 3600 V

So, the potential difference between the plates is 3600 V.