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To stretch a certain spring by 3.00 cm from its equilibrium position requires how much work?

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Final answer:

To stretch a certain spring by 3.00 cm, it requires 0.054 Joules of work.

Step-by-step explanation:

The work required to stretch a spring by 3.00 cm can be calculated using the formula PE = 1/2 kx^2, where PE is the potential energy, k is the spring constant, and x is the displacement. In this case, the displacement is 3.00 cm and the potential energy can be calculated as PE = (1/2)(k)(0.030 m)^2 = 0.054 J.

User Akanksha Rathore
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