Final answer:
The given circuit is a high-pass filter represented by a capacitor connected in series with a resistor. The output voltage, Vout, is determined by the formula Vout = Vin / (1 + (1 / (R^2 * C^2 * s^2))). For high frequencies, Vout is larger, while for low frequencies, Vout approximates to 0.
Step-by-step explanation:
The given circuit consists of a high-pass filter, which is represented by a capacitor connected in series with a resistor. The output voltage, Vout, can be determined using the formula Vout = Vin / (1 + (1 / (R^2 * C^2 * s^2))). Here, Vin is the input voltage, R is the resistance, C is the capacitance, and s is the frequency in rad/s.
For high frequencies, where s is large, the term 1 / (R^2 * C^2 * s^2) becomes small, resulting in a larger Vout. On the other hand, for low frequencies, where s is small, the term 1 / (R^2 * C^2 * s^2) becomes large, approximating Vout to 0.