Final answer:
The trace of the quadric surface x^2y^2 - z^2 = 36 with the plane x = k is a hyperbolic trace.
Step-by-step explanation:
The given quadric surface equation is x2 y2 - z2 = 36. The trace of a quadric surface with the plane x = k is obtained by substituting k for x in the equation and finding the value of y and z. So, for the given equation, when x = k, the trace would be y2 - z2 = 36. This is a hyperbolic trace.