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What is the mass of solute in 200.0 L of a 1.556M solution of KBr ?

A. 1.530×10⁴ g
B. 0.9258 g
C. 2.631 g
D. 3.703×10⁴g

User Kimi Chiu
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1 Answer

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Final answer:

To determine the mass of solute in a solution, you multiply the molarity by the volume of the solution to find the number of moles, and then convert the moles to grams using the molar mass of the solute. For a 1.556M KBr solution with a volume of 200.0 L, the calculation results in a solute mass of 3.703×10⁴ g.

Step-by-step explanation:

To calculate the mass of solute in a given volume of solution with a known molarity, follow these steps:

  1. Determine the number of moles of solute present in the solution by using the molarity and the volume of the solution. Molarity (M) is defined as moles of solute per liter of solution. Since the solution is 1.556M and we have 200.0L, multiply the molarity by the volume.
  2. Once you have the number of moles, use the molar mass of the solute to convert moles to grams. For KBr (potassium bromide), the molar mass can be calculated by adding the atomic mass of potassium (K) and bromine (Br).
  3. After calculating the mass of the solute, compare it with the given options to determine the correct answer.

The calculation will look like this:

  • Number of moles of KBr = Molarity × Volume = 1.556 moles/L × 200.0L = 311.2 moles
  • Molar mass of KBr = Atomic mass of K + Atomic mass of Br = 39.10 g/mol + 79.90 g/mol = 119.00 g/mol
  • Mass of KBr = Number of moles × Molar mass = 311.2 moles × 119.00 g/mol = 37032.8 g or 3.703×10⁴ g

The answer is D. 3.703×10⁴ g

User PrisonMonkeys
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