Question

Complete the PrintVals function to print each array element on a separate line.

void PrintVals(int arrayVals[], int numElements) {
int i;
for(i = 0; i < numElements; ++i) {
cout << arrayVals[i] << endl;
}
}

Answer 1

The student's question pertains to completing a C++ function to print each element of an array on its own line, using a for loop and standard output (cout).

Step-by-step explanation:

The student is asking for assistance in completing a function in programming that prints each element of an array on a separate line. Here is the completed PrintVals function:

void PrintVals(int arrayVals[], int numElements) {
int i;
for(i = 0; i < numElements; ++i) {
cout << arrayVals[i] << endl;
}
}

The function uses a for loop to iterate through the elements of the array. Within the loop, each element is accessed using arrayVals[i] and printed out with a newline character, endl, ensuring that each element appears on its own line. It is essential that this loop continues to iterate while i is less than the number of elements in the array, numElements, to avoid accessing elements outside the bounds of the array.