Question

A small telescope has a concave mirror with a 2.20 m radius of curvature for its objective. Its eyepiece is a 4.15 cm focal length lens.

(a) What is the telescope's angular magnification?
(b) What angle in degrees is subtended by a 23,000 km diameter sunspot?
(c) What is the angle in degrees of its telescopic image? (Include the sign of the value in your answer.)

Answer 1

The angular magnification of the telescope is -50, but the angle subtended by the sunspot and its telescopic image cannot be calculated without the distance.

Step-by-step explanation:

(a) What is the telescope's angular magnification?

To calculate the angular magnification, we will use the formula:

Angular Magnification (M) = - (fo/fe)

Where fo is the focal length of the objective lens and fe is the focal length of the eyepiece lens. In this case, fo = 200 cm and fe = 4 cm.

So the angular magnification is:

M = - (200/4) = -50.

(b) What angle is subtended by a 25,000 km diameter sunspot?

To find the angle subtended by the sunspot, we will use the formula:

Angle (in radians) = Diameter/Distance

The distance is not given, so we cannot calculate the angle subtended.

(c) What is the angle its telescopic image?

The angle of the telescopic image can be calculated using the formula:

Angle (in degrees) = M x Angle (in degrees) of the object

Since the angle subtended by the sunspot is not given, we cannot calculate the angle of its telescopic image.