214k views
0 votes
Given that z is a standard normal random variable,

find z for each situation. (Round your answers to two decimal
places.)
(a) The area to the left of z is 0.2119.
(b) The area between −z and z is 0.9030.
(c) The area between −z and z is 0.2052.
(d) The area to the left of z is 0.9948.
(e) The area to the right of z is 0.5793.

User Darkerstar
by
8.4k points

1 Answer

4 votes

Final answer:

To find z for each situation, use the z-table to locate the area under the normal curve to the left of each z-score.

Step-by-step explanation:

To find z for each situation, we can use the z-table to locate the area under the normal curve to the left of each z-score.

(a) The area to the left of z is 0.2119. We can search the z-table to find the z-score that corresponds to an area of 0.2119. Let's call this z1. From the z-table, we find that z1 is approximately -0.79.

(b) The area between -z and z is 0.9030. We need to find the z-scores that correspond to an area of 0.9030. Let's call these z2 and z3. From the z-table, we find that z2 is approximately -1.75 and z3 is approximately 1.75.

(c) The area between -z and z is 0.2052. We need to find the z-scores that correspond to an area of 0.2052. Let's call these z4 and z5. From the z-table, we find that z4 is approximately -0.85 and z5 is approximately 0.85.

(d) The area to the left of z is 0.9948. We can search the z-table to find the z-score that corresponds to an area of 0.9948. Let's call this z6. From the z-table, we find that z6 is approximately 2.29.

(e) The area to the right of z is 0.5793. We can use the fact that the total area under the normal curve is 1. So, the area to the left of z is 1 - 0.5793 = 0.4207. We can search the z-table to find the z-score that corresponds to an area of 0.4207. Let's call this z7. From the z-table, we find that z7 is approximately -0.22.

User Sunil Vurity
by
8.1k points