Question

Two 4.0kg masses are 1.0m apart on a frictionless table. Each has 1.0μC of charge. Part A What is the magnitude of the electric force on one of the masses?

Answer 1

The magnitude of the electric force between two masses with charges 1.0μC each and separated by 1.0m is 9 x 10^-7 N.

Step-by-step explanation:

The magnitude of the electric force between two masses can be calculated using Coulomb's law:

F = k * (q1 * q2) / r^2

Where:

• F is the magnitude of the electric force
• k is the Coulomb's constant (approximately 9 x 10^9 Nm^2/C^2)
• q1 and q2 are the charges of the masses (1.0μC in this case)
• r is the distance between the masses (1.0m in this case)

Substituting the values into the equation:

F = (9 x 10^9 Nm^2/C^2) * (1.0μC * 1.0μC) / (1.0m)^2

F = 9 x 10^-7 N

Therefore, the magnitude of the electric force on one of the masses is 9 x 10^-7 N.