Final answer:
The complete balanced neutralization equation for the reaction between acetic acid (HC2H3O2) and strontium hydroxide (Sr(OH)2) is 2HC2H3O2(aq) + Sr(OH)2(aq) → Sr(C2H3O2)2(s) + 2H2O(l), producing strontium acetate and water.
Step-by-step explanation:
When acetic acid (HC2H3O2) reacts with strontium hydroxide (Sr(OH)2), a neutralization reaction occurs. The complete balanced chemical equation, including the phases of the reactants and products, is as follows:
2HC2H3O2(aq) + Sr(OH)2(aq) → Sr(C2H3O2)2(s) + 2H2O(l)
The acetic acid is in aqueous form, as well as the strontium hydroxide, while the resultant strontium acetate (Sr(C2H3O2)2) is a solid and water (H2O) is a liquid. This is a double displacement reaction where the cations and anions exchange partners, leading to the formation of water and a salt, which in this case is assumed to be insoluble as per the instruction in the question.