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Let g(x,y)=cos(6x 2y). 1. Evaluate g(1,-2). 2. What is the range of g(x,y)?

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Final answer:

1. Evaluate g(1,-2) by substituting the given values into the function. 2. The range of g(x,y) is [-1, 1].

Step-by-step explanation:

1. To evaluate g(1,-2), substitute the given values into the function: g(x,y) = cos(6x 2y). So, g(1, -2) = cos(6(1) + 2(-2)).

Simplifying further, g(1, -2) = cos(6 - 4) = cos(2).

2. The range of g(x,y) refers to the set of all possible values that g can take on. For the function g(x,y) = cos(6x 2y), the range is [-1, 1] since the cosine function can only output values between -1 and 1 inclusively.

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