Final answer:
A heat quantity of 15.88 kJ is absorbed in the process of making 0.903 mol of CF4 from the reaction of carbon with fluorine gas, using the provided enthalpy change of -4,400 J for 0.25 moles.
Step-by-step explanation:
To calculate the quantity of heat absorbed in the reaction where carbon solid (C (s)) reacts with fluorine gas (F2 (g)) to produce carbon tetrafluoride (CF4 (g)), we need to use the reaction's enthalpy change. If we assume that the enthalpy change (ΔH) provided in the reference is for the formation of CF4, the process is as follows:
According to the given data, the enthalpy change for the formation of carbon tetrafluoride (CF4) from its elements is -4,400 J for 0.25 moles. To find the enthalpy change for one mole of CF4, we multiply by four:
ΔH for 1 mole CF4 = -4,400 J × 4 = -17,600 J, or -17.6 kJ.
To find the quantity of heat absorbed for 0.903 moles of CF4, use the proportional relationship:
Heat for 0.903 moles CF4 = -17.6 kJ/mol × 0.903 mol = -15.88 kJ (rounded to two decimal places).
Therefore, 15.88 kJ of heat is absorbed in the process of making 0.903 mol of CF4.