198k views
3 votes
Find the absolute extrema of the function (if any exist) on each interval. If an answer does not exist, enter dne. f(x) = 2x - 3?

User Shaheen G
by
7.7k points

1 Answer

3 votes

Final answer:

The absolute extrema of the function f(x) = 2x - 3 on the interval 0 ≤ x ≤ 20 are -3 and 37.

Step-by-step explanation:

The function f(x) = 2x - 3 is a linear function, so it is a straight line with a slope of 2. Since the domain of the function is 0 ≤ x ≤ 20, the graph of the function is a line segment between x = 0 and x = 20, inclusive.

The absolute extrema of a function on an interval occur at either the endpoints of the interval or at critical points where the derivative is zero or undefined. Since f(x) = 2x - 3 is a straight line, it has no critical points and the endpoints of the interval are the only potential locations for absolute extrema.

At x = 0, f(x) = 2(0) - 3 = -3, and at x = 20, f(x) = 2(20) - 3 = 37. Therefore, the absolute minimum is -3 and the absolute maximum is 37.

User Nichole
by
7.2k points