Final Answer:
The potential difference between point A and point B is 10 volts.
Step-by-step explanation:
The potential difference (V) between two points in an electric field is the work done (W) in moving a positive test charge (q) from one point to the other, divided by the magnitude of the charge. Mathematically, it is expressed as V = W/q.
In this scenario, let's consider moving a charge of 1 Coulomb from point A to point B. The formula becomes V = W/1 C. Given that the work done is equal to the product of the charge and the potential difference (W = qV), we can rewrite the equation as V = qV/1 C. Solving for V, we find that the potential difference is 10 volts.
The concept of potential difference is crucial in understanding electrical circuits. It represents the energy per unit charge required to move a charge between two points. In the context of this question, a 10-volt potential difference indicates that it takes 10 joules of energy to move a 1-Coulomb charge from point A to point B.
This energy is transformed into various forms, such as heat or light, depending on the components in the circuit. Engineers and physicists use potential difference as a fundamental parameter in designing and analyzing electrical systems, ensuring efficient energy transfer and proper functioning of devices.
In summary, the 10-volt potential difference between point A and point B signifies the energy required to move a unit positive charge between these points. This understanding is foundational in the field of electrical engineering and plays a pivotal role in designing and optimizing various electronic systems.