Final answer:
The student is looking to solve a quadratic equation and the solution involves using the quadratic formula. By substituting the values into the formula, we obtain the potential solutions for x, which are x = 0.0216 or x = -0.0224.
Step-by-step explanation:
The student's question involves evaluating an expression using given functions, specifically the quadratic formula. The expression mentioned in the typos does not directly correspond to a well-defined problem, but it seems that the student is attempting to solve a quadratic equation.
To solve a quadratic equation of the form ax² + bx + c = 0, we use the quadratic formula:
x = √(-b ± √(b² - 4ac)) / (2a)
In this case, we have an equation x² + 1.2 x 10^-2x - 6.0 × 10^-3 = 0, which appears to be x² + 0.012x - 0.006 = 0. To solve for x, we plug the coefficients into the quadratic formula, yielding the solutions x = 0.0216 or x = -0.0224, indicating the values of x that satisfy the equation.