Question

A rocket is launched in the air. Its height, in meters above sea level, as a function of time, in seconds, is given by h(t) = -4.9t² + 229t + 234. What is the height of the rocket at t = 5 seconds?

Answer 1

The height of the rocket at t = 5 seconds is calculated using the quadratic function h(t) and the given time value. The resulting height of the rocket is 1256.5 meters.

Step-by-step explanation:

The height of the rocket at t = 5 seconds is determined by substituting the value of t into the given function h(t) = -4.9t² + 229t + 234. Following through with the calculation:

h(5) = -4.9 * (5)² + 229 * 5 + 234
= -4.9 * 25 + 1145 + 234
= -122.5 + 1145 + 234
= 1256.5 m

Therefore, the height of the rocket at 5 seconds is 1256.5 meters.