Question

Write a loop that sets newscores to oldscores rotated once left, with element 0 copied to the end. For example, if oldscores = 10, 20, 30, 40, then newscores = 20, 30, 40, 10.

Answer 1

To rotate the elements in an array once to the left, you can use a loop and some temporary variables. The loop runs from index 0 to the second-to-last index in the array, copying each element to the corresponding index in a new array, except for the first element which is copied to the last index.

Step-by-step explanation:

To rotate the elements in an array once to the left, you can use a loop and some temporary variables. Here's an example:

int[] oldscores = {10, 20, 30, 40};
int[] newscores = new int[oldscores.length];

// Copying elements from the oldscores array to the newscroes array in a rotated fashion
for (int i = 0; i < oldscores.length - 1; i++) {
newscores[i] = oldscores[i+1];
}

// Copying the first element from oldscores array to the last position in the newscroes array
newscores[newscores.length - 1] = oldscores[0];

In this example, the loop runs from index 0 to the second-to-last index in the oldscores array. It copies each element to the corresponding index in the newscroes array, except for the first element which is copied to the last index.