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Determine the charge stored by C1 when C1 = 20 μF, C₂ = 10 μF, C₃ = 30 μF, and V0 = 18 V.

User Redimp
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Final answer:

The charge Q1 stored by a 20 µF capacitor (C1) when subjected to an 18 V voltage (V0) is 360 µC. This is found using the formula Q = CV.

Step-by-step explanation:

To determine the charge stored by capacitor C1 when C1 = 20 µF and V0 = 18 V, we use the formula for charge stored in a capacitor, which is Q = CV. The charge Q is the product of the capacitance C and the voltage V across the capacitor. Therefore, for C1, the charge Q1 stored can be calculated as:

Q1 = C1 × V0

Q1 = 20 µF × 18 V

Q1 = 360 µC (microCoulombs)

As this calculation is straightforward, we can be confident that the capacitor with a capacitance of 20 µF charged to a voltage of 18 V will store 360 µC of charge.

User Fho
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