Final answer:
The charge Q1 stored by a 20 µF capacitor (C1) when subjected to an 18 V voltage (V0) is 360 µC. This is found using the formula Q = CV.
Step-by-step explanation:
To determine the charge stored by capacitor C1 when C1 = 20 µF and V0 = 18 V, we use the formula for charge stored in a capacitor, which is Q = CV. The charge Q is the product of the capacitance C and the voltage V across the capacitor. Therefore, for C1, the charge Q1 stored can be calculated as:
Q1 = C1 × V0
Q1 = 20 µF × 18 V
Q1 = 360 µC (microCoulombs)
As this calculation is straightforward, we can be confident that the capacitor with a capacitance of 20 µF charged to a voltage of 18 V will store 360 µC of charge.