Question

Consider the reaction: Cl2(g) + 3F₂(g) → 2ClF₃(g). If the concentration of ClF₃ increases from 0.30 M to 0.95 M over the course of 25.0 seconds, what is the overall rate of the reaction?

Answer 1

The overall rate of the reaction Cl₂(g) + 3F₂(g) → 2ClF₃(g) is 0.026 M/s, calculated by dividing the change in concentration of ClF₃ (0.65 M) by the time interval (25.0 seconds).

Step-by-step explanation:

To calculate the overall rate of the reaction Cl₂(g) + 3F₂(g) → 2ClF₃(g), we need to consider the change in concentration of ClF₃ over time. The concentration of ClF₃ increased from 0.30 M to 0.95 M over the course of 25.0 seconds.

Firstly, we calculate the change in concentration (Δ[ClF₃]) which is 0.95 M - 0.30 M = 0.65 M. Next, we determine the change in time (Δt), which is 25.0 seconds. The rate of the reaction can be calculated using the formula:

Rate = Δ[ClF₃] / Δt

Plugging the values into the equation gives us:

Rate = 0.65 M / 25.0 s = 0.026 M/s