Final answer:
To calculate the mass of CuSO4 remaining when 19 g of CuSO4· H2O is heated until the solid is anhydrous, subtract the mass of the water lost from the initial mass of CuSO4·H2O. The mass of CuSO4 remaining is 16.86 g.
Step-by-step explanation:
To calculate the mass of CuSO4 remaining when 19 g of CuSO4· H2O is heated until the solid is anhydrous, we need to consider the molar mass of CuSO4·H2O and the molar mass of CuSO4. The molar mass of CuSO4·H2O is 159.62 g/mol, and the molar mass of CuSO4 is 159.62 g/mol. Assuming the reaction goes to completion with 100% yield, the mass of CuSO4 remaining would be equal to the initial mass of CuSO4·H2O minus the mass of the water that is lost upon heating. The molar mass of water (H2O) is 18.02 g/mol.
First, let's calculate the number of moles of CuSO4·H2O:
(19 g) / (159.62 g/mol) = 0.119 moles
Next, let's calculate the mass of water lost:
(0.119 moles) * (18.02 g/mol) = 2.14 g
Finally, let's calculate the mass of CuSO4 remaining:
19 g - 2.14 g = 16.86 g