Answer:
130.24m
Step-by-step explanation:
According to the question ,
- Acceleration (a) = 2.4m/s²
- Initial velocity (u) = 0m/s
- Final velocity (v) = 90km/hr = 25m/s
- Displacement = ?
Using the third equation of motion namely ,
2as = v² - u²
2(2.4m/s²) * s = (25m/s)² - 0²
s = 625m²s-²/2*2.4 m/s² .
s = 130.24 m
Hence the distance travelled during this interval is 130.24 m.