Final answer:
The rate of consumption of B in the reaction A + 2B → C with an initial rate of 0.100 m/s is 0.200 m/s, as B is consumed at twice the rate of A due to the reaction stoichiometry.
Step-by-step explanation:
The initial rate of the reaction A + 2B → C is given as 0.100 m/s. To find the rate of consumption of B, we need to look at the stoichiometry of the reaction. For every 1 mole of A consumed, 2 moles of B are consumed.
This means that the rate of consumption of B will be twice the rate of consumption of A. Since the initial rate of the reaction represents the rate of consumption of A, the rate of consumption of B would be 2 × 0.100 m/s = 0.200 m/s.